Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ch-1697: NEET 2012 Chemistry - Class 11 AIPM-2012-Ch-1697 Solution: In a zero-order reaction for every \(10^ C\) rise of…

In a zero-order reaction for every 10∘C10^\circ C rise of temperature the rate is doubled. If the temperature is increased from 10∘C10^\circ C to 100∘C100^\circ C the rate of the reaction will become 256 times 512 times 64 times 128 times

Multiple Choice Options

  • A 10.52 cal/(mol K)
  • B 21.04 cal/(mol K)
  • C 5.260 cal/(mol K)
  • D 0.526 cal/(mol K)

Step-by-Step Verified Solution

H 2 O( l ) _ H 2 O(s) �H = 1.435 Kcal/mol T = 0 + 273K = 273K _ S = _ H T _ _ S = 1.435 273 = 5.26 _ 10 -3 kcal/mol K _ _ S = 5.260 cal/mol K

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