Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ch-1645: NEET 2012 Chemistry - Class 11 AIPM-2012-Ch-1645 Solution: The orbital angular momentum of a p-electron is given as \(…

The orbital angular momentum of a p-electron is given as h2π\frac{h}{\sqrt{2}\pi} 3h2π\sqrt{3}\frac{h}{2\pi} 3hπ\sqrt{3}\frac{h}{\pi} 6h2π\sqrt{6}\frac{h}{2\pi}

Multiple Choice Options

  • A h2π{h \over {\sqrt 2 \pi }} 2 _ � h _
  • B 3h2π\sqrt 3 {h \over {2\pi }} 3 _ 2 � h _
  • C 32hπ\sqrt {{3 \over 2}} {h \over \pi } 2 3 _ _ � h _
  • D 6h2π\sqrt 6 {h \over {2\pi }} 6 _ 2 � h _

Step-by-Step Verified Solution

Orbital angular momentum (m) = l ( l + 1 ) h 2 � For p-electrons; l = 1 Thus, m = l ( l + 1 ) h 2 � = 2 h 2 � = h 2 �

Related Learning Resources & Exam Preparation

NEET PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring