Verified Solution • 2025–26 Session moderate

QAIPM-2012-Ch-1625: NEET 2012 Chemistry - Class 12 AIPM-2012-Ch-1625 Solution: Standard reduction potentials of the half reactions are given…

Standard reduction potentials of the half reactions are given below: F2(g)+2e−→2F−(aq);E∘=+2.85 VF_2(g) + 2e^- \rightarrow 2F^-(aq); E^\circ = +2.85\ \text{V} Cl2(g)+2e−→2Cl−(aq);E∘=+1.36 VCl_2(g) + 2e^- \rightarrow 2Cl^-(aq); E^\circ = +1.36\ \text{V} Br2(l)+2e−→2Br−(aq);E∘=+1.06 VBr_2(l) + 2e^- \rightarrow 2Br^-(aq); E^\circ = +1.06\ \text{V} I2(s)+2e−→2I−(aq);E∘=+0.53 VI_2(s) + 2e^- \rightarrow 2I^-(aq); E^\circ = +0.53\ \text{V} The strongest oxidising and reducing agents respectively are F2F_2 and I−I^- Br2Br_2 and Cl−Cl^- Cl2Cl_2 and Br−Br^- Cl2Cl_2 and I2I_2

Multiple Choice Options

  • A F 2 and I −- _
  • B Br 2 and Cl −- _
  • C Cl 2 and Br −- _
  • D Cl 2 and I 2

Step-by-Step Verified Solution

Higher the value of reduction potential higher will be the oxidising power whereas the lower the value of reduction potential higher will be the reducing power.

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