Verified Solution • 2025–26 Session moderate

QAIPMT-2011-Ph-1925: NEET 2011 Physics - Class 12 AIPMT-2011-Ph-1925 Solution: If power dissipated in the \(9 \) resistor in the circuit shown …

If power dissipated in the 9Ω9\Omega resistor in the circuit shown is 36 watt, the potential difference across the 2Ω2\Omega resistor is

Multiple Choice Options

  • A 4 volt
  • B 8 volt
  • C 10 volt
  • D 2 volt

Step-by-Step Verified Solution

We have, P = V 2 R _ 36 = V 2 9 _ V = 18 Current passing through the 9 � resistor is i 1 = V R = 18 9 = 2 A The 9 � and 6 � resistors are in parallel, therefore i 1 = 6 9 + 6 _ i where i is the current delivered by the battery. _ i = 2 _ 15 6 = 5 A Thus, potential difference across 2 � resistor is V = iR = 5 _ 2 = 10V

Related Learning Resources & Exam Preparation