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QAIPMT-2011-Ph-1923: NEET 2011 Physics - Class 12 AIPMT-2011-Ph-1923 Solution: A current carrying closed loop in the form of a right angle…

A current carrying closed loop in the form of a right angle isosceles triangle ABC is placed in uniform magnetic field acting along AB. If the magnetic force on the arm BC is

\vec{F}

, the force on the arm AC is

Multiple Choice Options

A $-\sqrt{2}\vec{F}$
B $-\vec{F}$
C $\vec{F}$
D $\sqrt{2}\vec{F}$

Step-by-Step Verified Solution

Here, F _ B C = F _ _ F _ A B = 0 The net magnetic force on a current carrying closed loop in a uniform magnetic field is zero. _ F _ A B + F _ B C + F _ A C = 0 _ F _ A C = _ F _ B C ( _ F _ A B = 0 )

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