Verified Solution • 2025–26 Session moderate

QAIPMT-2011-Ph-1901: NEET 2011 Physics - Class 11 AIPMT-2011-Ph-1901 Solution: The instantaneous angular position of a point on a rotating…

The instantaneous angular position of a point on a rotating wheel is given by the equation θ(t)=2t3−6t2\theta(t)=2t^3-6t^2. The torque on the wheel becomes zero at

Multiple Choice Options

  • A t=1 st=1\ \text{s}
  • B t=0.5 st=0.5\ \text{s}
  • C t=0.25 st=0.25\ \text{s}
  • D t=2 st=2\ \text{s}

Step-by-Step Verified Solution

When angular acceleration (a) is zero then torque on the wheel becomes zero. _ ( t ) = 2 t 3 _ 6 t 2 _ d _ d t = 6 t 2 _ 12 t _ _ = d 2 _ d t 2 = 12 t _ 12 = 0 _ t = 1 sec.

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