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QAIPM-2011-Ph-1892: NEET 2011 Physics - Class 11 AIPM-2011-Ph-1892 Solution: During an isothermal expansion a confined ideal gas does -150 J …
During an isothermal expansion a confined ideal gas does -150 J of work against its surroundings. This implies that 150 J of heat has been removed from the gas 300 J of heat has been added to the gas no heat is transferred because the process is isothermal 150 J of heat has been added to the gas
Multiple Choice Options
- A I 0 _ + M L 2 /2
- B I 0 _ + M L 2 /4
- C I 0 _ + 2 M L 2
- D I 0 _ + M L 2
Step-by-Step Verified Solution
By the theorem of parallel axes, the moment
of inertia of a body about any axis is equal to the
sum of the moment of inertia about a parallel axis
through the centre of mass and Ma 2
, where M is the mass of the body and a is the separation between
the two axes.
Therefore, the moment of inertia of the rod about
an axis passing through one of its ends and
perpendicular to its length is
I = I 0 + M (L/2) 2
= I 0 + ML 2 /4