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QAIPM-2011-Ph-1889: NEET 2011 Physics - Class 11 AIPM-2011-Ph-1889 Solution: A boy standing at the top of a tower of 20 m height drops a…

A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 m s−2^{-2}, the velocity with which it hits the ground is

Multiple Choice Options

  • A 10.0 m/s
  • B 20.0 m/s
  • C 40.0 m/s
  • D 5.0 m/s

Step-by-Step Verified Solution

We know, v 2 = u 2 + 2gh Here u = 0 _ v = 2 g h = 2 _ 10 _ 20 = 20 m/s

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