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QAIPM-2011-Ph-1831: NEET 2011 Physics - Class 12 AIPM-2011-Ph-1831 Solution: An electron in the hydrogen atom jumps from excited state n to…
An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, then the value of n is
Multiple Choice Options
- A 2
- B 3
- C 4
- D 5
Step-by-Step Verified Solution
KE max = 10eV
_ = 2.75 eV
Total incident energy
E = _ + KE max = 12.75 eV
_ Energy is released when electron jumps from
the excited state n to the ground state.
_ E 4 � E 1 = {� 0.85 � (�13.6) ev}
= 12.75eV
_ value of n = 4