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QAIPM-2011-Ph-1823: NEET 2011 Physics - Class 11 AIPM-2011-Ph-1823 Solution: Two particles are oscillating along two close parallel straight …
Two particles are oscillating along two close parallel straight lines side by side with the same frequency and amplitudes. They pass each other moving in opposite directions when their displacement is half of the amplitude. The mean positions of the two particles lie on a straight line perpendicular to the paths of the two particles. The phase difference is 0
Multiple Choice Options
- A 45 o
- B 60 o
- C tan _ 1 ( 2 1 _ )
- D tan _ 1 ( 2 3 _ _ )
Step-by-Step Verified Solution
Let _ be elevation angle of the projectile at its
highest point as seen from the point of projection
O and _ be angle of projection with the horizontal.
From figure, tan _ = H R / 2 ....(1)
In case of projectile motion
Maximum height H = u 2 sin 2 _ 2 g
Horizontal range, R = u 2 sin _ _ g
Substituting these values of H and R in (1), we get
tan _ _ = u 2 sin 2 _ 2 g u 2 sin _ 2 _ 2 g
tan _ _ = sin 2 _ sin _ 2 _ = sin 2 _ 2 sin _ _ cos _ _
= 1 2 tan _ _
tan _ _ = 1 2 tan _ 45 _ = 1 2
Here, _ = 45�
_ tan _ _ = 1 2 tan _ 45 _ = 1 2 ( _ tan _ 45 _ = 1 )
_ = tan _ 1 ( 1 2 )