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QAIPM-2011-Ph-1818: NEET 2011 Physics - Class 12 AIPM-2011-Ph-1818 Solution: Two radioactive nuclei P and Q in a given sample decay into a…

Two radioactive nuclei P and Q in a given sample decay into a stable nucleus R. At time t = 0 number of P species are 4N04N_0 and that of Q are N0N_0. Half-life of P (for conversion to R) is 1 minute where as that of Q is 2 minutes. Initially there are no nuclei of R present in the sample. When number of nuclei of P and Q are equal the number of nuclei of R present in the sample would be 2N02N_0 3N03N_0 9N02\frac{9N_0}{2} 5N02\frac{5N_0}{2}

Multiple Choice Options

  • A 5 mA
  • B 10 mA
  • C 15 mA
  • D 20 mA

Step-by-Step Verified Solution

Voltage across 250 � resistance = 20 V � 15 V = 5 V Now current through 250 � resistance: 5/250 = 20 mA If voltage across load resistance 1 k � is 15 V, then current through 1 k� is 15/1000 = 15 mA The current through the zener diode is = Current through 250 � resistance � Current through 1 k � resistance. = 20 - 15 = 5 mA

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