Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ph-1816: NEET 2011 Physics - Class 11 AIPM-2011-Ph-1816 Solution: A mass m moving horizontally (along the x-axis) with velocity v …

A mass m moving horizontally (along the x-axis) with velocity v collides and sticks to a mass of 3m moving vertically upwards (along the y-axis) with velocity 2v. The final velocity of the combination is

Multiple Choice Options

  • A 32vi^+14vj^\frac{3}{2}v\hat{i}+\frac{1}{4}v\hat{j}
  • B 14vi^+32vj^\frac{1}{4}v\hat{i}+\frac{3}{2}v\hat{j}
  • C 13vi^+23vj^\frac{1}{3}v\hat{i}+\frac{2}{3}v\hat{j}
  • D 23vi^+13vj^\frac{2}{3}v\hat{i}+\frac{1}{3}v\hat{j}

Step-by-Step Verified Solution

According to conservation of momentum, we get m v i ^ + ( 3 m ) 2 v j ^ = ( m + 3 m ) v _ _ where v _ _ is the final velocity after collision v _ _ = 1 4 v i ^ + 6 4 v j ^ = 1 4 v i ^ + 3 2 v j ^

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