Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ph-1815: NEET 2011 Physics - Class 12 AIPM-2011-Ph-1815 Solution: A mass m moving horizontally (along the x-axis) with velocity v …

A mass m moving horizontally (along the x-axis) with velocity v collides and sticks to a mass of 3m moving vertically upwards (along the y-axis) with velocity 2v. The final velocity of the combination is 32vi^+14vj^\frac{3}{2}v\hat{i} + \frac{1}{4}v\hat{j} 14vi^+32vj^\frac{1}{4}v\hat{i} + \frac{3}{2}v\hat{j} 13vi^+23vj^\frac{1}{3}v\hat{i} + \frac{2}{3}v\hat{j} 23vi^+13vj^\frac{2}{3}v\hat{i} + \frac{1}{3}v\hat{j}

Multiple Choice Options

  • A 3qQ4πε0a{{3qQ} \over {4\pi {\varepsilon _0}a}} 4 � _ 0 _ a 3 qQ _
  • B 3qQ8πε0a{{3qQ} \over {8\pi {\varepsilon _0}a}} 8 � _ 0 _ a 3 qQ _
  • C qQ4πε0a{{qQ} \over {4\pi {\varepsilon _0}a}} 4 � _ 0 _ a qQ _
  • D zero

Step-by-Step Verified Solution

AC = BC V D = V E We have, W = Q (V E � V D ) _ W = 0

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