Verified Solution • 2025–26 Session
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QAIPM-2011-Ph-1807: NEET 2011 Physics - Class 11 AIPM-2011-Ph-1807 Solution: A mass of diatomic gas (\( =1.4\)) at a pressure of 2…
A mass of diatomic gas () at a pressure of 2 atmospheres is compressed adiabatically so that its temperature rises from to . The pressure of the gas in the final state is
Multiple Choice Options
- A 8 atm
- B 28 atm
- C 68.7 atm
- D 256 atm
Step-by-Step Verified Solution
T 1 = 273 + 27 = 300K
T 2 = 273 + 927 = 1200K
For adiabatic process,
P 1 _ _ T _ = constant
_ P 1 1 _ _ T 1 _ = P 2 1 _ _ T 2 _
_ ( P 2 P 1 ) 1 _ _ = ( T 1 T 2 ) _
_ ( P 1 T 2 ) 1 _ _ = ( T 2 T 1 ) _
( P 1 P 2 ) 1 _ 1.4 = ( 1200 300 ) 1.4
( P 1 P 2 ) _ 0.4 = ( 4 ) 1.4
( P 2 P 1 ) 0.4 = 4 1.4
P 2 = P 1 4 ( 1.4 0.4 ) = P 1 4 ( 7 2 )
= P 1 (2 7 ) = 2 _ 128 = 256 atm