Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ph-1804: NEET 2011 Chemistry - Class 11 AIPM-2011-Ph-1804 Solution: In qualitative analysis, the metals of group I can be separated …

In qualitative analysis, the metals of group I can be separated from other ions by precipitating them as chloride salts. A solution initially contains Ag+Ag^+ and Pb2+Pb^{2+} at a concentration of 0.10 M. Aqueous HCl is added to this solution until the Cl−Cl^- concentration is 0.10 M. What will the concentrations of Ag+Ag^+ and Pb2+Pb^{2+} be at equilibrium? (KspK_{sp} for AgCl = 1.8×10−101.8\times10^{-10}, KspK_{sp} for PbCl2=1.7×10−5PbCl_2 = 1.7\times10^{-5})

Multiple Choice Options

  • A [Ag+]=1.8×10−7 M, [Pb2+]=1.7×10−6 M[Ag^+]=1.8\times10^{-7}\ \text{M},\ [Pb^{2+}]=1.7\times10^{-6}\ \text{M}
  • B [Ag+]=1.8×10−11 M, [Pb2+]=8.5×10−5 M[Ag^+]=1.8\times10^{-11}\ \text{M},\ [Pb^{2+}]=8.5\times10^{-5}\ \text{M}
  • C [Ag+]=1.8×10−9 M, [Pb2+]=1.7×10−3 M[Ag^+]=1.8\times10^{-9}\ \text{M},\ [Pb^{2+}]=1.7\times10^{-3}\ \text{M}
  • D [Ag+]=1.8×10−11 M, [Pb2+]=1.7×10−4 M[Ag^+]=1.8\times10^{-11}\ \text{M},\ [Pb^{2+}]=1.7\times10^{-4}\ \text{M}

Step-by-Step Verified Solution

K sp [AgCl] = [Ag + ][Cl - ] _ [Ag + ] = 1.8 _ 10 _ 10 10 _ 1 = 1.8 _ 10 _ 9 M K sp [PbCl 2 ] = [Pb 2+ ][Cl - ] 2 _ [Pb 2+ ] = 1.7 _ 10 _ 5 10 _ 1 _ 10 _ 1 = 1.7 _ 10 _ 3 M

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