Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ch-1881: NEET 2011 Chemistry - Class 11 AIPM-2011-Ch-1881 Solution: Enthalpy change for the reaction, \(4H(g) 2H_2(g)\) is…

Enthalpy change for the reaction, 4H(g)→2H2(g)4H(g)\rightarrow 2H_2(g) is −869.6-869.6 kJ. The dissociation energy of H-H bond is

Multiple Choice Options

  • A 434.8 kJ
  • B −869.6-869.6 kJ
  • C +434.8 kJ
  • D +217.4 kJ

Step-by-Step Verified Solution

4H(g) _ 2H 2 (g),    �H = � 869.6 kJ Reverse the above equation 2H 2 (g) _ 4H(g),    �H = + 869.6 kJ Divide the above equation by 2, H 2 (g) _ 2H(g), _ H = 869.6 2 kJ = 434.8 kJ

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