Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ch-1868: NEET 2011 Chemistry - Class 12 AIPM-2011-Ch-1868 Solution: The d-electron configurations of \(Cr^{2+}\), \(Mn^{2+}\),…

The d-electron configurations of Cr2+Cr^{2+}, Mn2+Mn^{2+}, Fe2+Fe^{2+} and Co2+Co^{2+} are d4d^4, d5d^5, d6d^6 and d7d^7 respectively. Which one of the following will exhibit minimum paramagnetic behaviour? (At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

Multiple Choice Options

  • A [Mn(H2O)6]2+[Mn(H_2O)_6]^{2+}
  • B [Fe(H2O)6]2+[Fe(H_2O)_6]^{2+}
  • C [Co(H2O)6]2+[Co(H_2O)_6]^{2+}
  • D [Cr(H2O)6]2+[Cr(H_2O)_6]^{2+}

Step-by-Step Verified Solution

[Mn(H 2 O) 6 ] 2+ : Mn 2+ = 3d 5 _ Number of unpaired electron = 5 [Fe(H 2 O) 6 ] 2+ : Fe 2+ = 3d 6 _ Number of unpaired electrons = 4 [Co(H 2 O) 6 ] 2+ : Co 2+ = 3d 7 _ Number of unpaired electrons = 3 [Cr(H 2 O) 6 ] 2+ : Cr 2+ = 3d 4 Number of unpaired electrons = 4 Minimum paramagnetic behaviour is shown by [Co(H 2 O) 6 ] 2+ .

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