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QAIPM-2011-Ch-1867: NEET 2011 Chemistry - Class 11 AIPM-2011-Ch-1867 Solution: A gaseous mixture was prepared by taking equal mole of CO and…
A gaseous mixture was prepared by taking equal mole of CO and . If the total pressure of the mixture was found 1 atmosphere, the partial pressure of the nitrogen () in the mixture is
Multiple Choice Options
- A 0.5 atm
- B 0.8 atm
- C 0.9 atm
- D 1 atm
Step-by-Step Verified Solution
Number of moles _ n CO = n N 2
Volume of container is same. So, V CO = V N 2
.
Also,
temperature is same for both the gases thus,
T CO = T N 2
According to ideal gas equation,
PV = nRT
Now, V, n, R and T for both gases are same. So,
P CO = P N 2
Now, total pressure is 1 atm and according to
Dalton�s law of partial pressure,
P CO + P N 2
= 1 atm
_ 2P N 2
= 1 atm { _ P CO = P N 2
}
_ P N 2
= 0.5 atm