Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ch-1797: NEET 2011 Chemistry - Class 12 AIPM-2011-Ch-1797 Solution: 200 mL of an aqueous solution of a protein contains 1.26 g of…

200 mL of an aqueous solution of a protein contains 1.26 g of it. The osmotic pressure of this solution at 300 K is found to be 2.57×10−32.57\times10^{-3} bar. The molar mass of protein will be (R = 0.083 L bar mol−1^{-1} K−1^{-1})

Multiple Choice Options

  • A 51022 g mol−1^{-1}
  • B 122044 g mol−1^{-1}
  • C 31011 g mol−1^{-1}
  • D 61038 g mol−1^{-1}

Step-by-Step Verified Solution

Osmotic pressure, � = CRT _ � = n V RT _ � V = w M RT M = w R T � V = 1.26 _ 0.083 _ 300 2.57 _ 10 _ 3 _ 200 1000 = 1.26 _ 0.083 _ 300 2.57 _ 10 _ 3 _ 0.2 = 61038 g mol �1

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