Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ch-1787: NEET 2011 Chemistry - Class 12 AIPM-2011-Ch-1787 Solution: Consider the following processes: \( H\ ( {kJ/mol})\) \(1/2A…

Consider the following processes: ΔH (kJ/mol)\Delta H\ (\text{kJ/mol}) 1/2A→B1/2A \rightarrow B +150 3B→2C+D3B \rightarrow 2C + D -125 E+A→2DE + A \rightarrow 2D +350 For B+D→E+2CB + D \rightarrow E + 2C ΔH\Delta H will be 525 kJ/mol -175 kJ/mol -325 kJ/mol 325 kJ/mol

Multiple Choice Options

  • A SnO 2
  • B CaO
  • C SiO 2
  • D CO 2

Step-by-Step Verified Solution

SnO 2 reacts with acid as well as base. So SnO 2 is an amphoteric. SnO 2 + 4HCl _ SnCl 2 + 2H 2 O SnO 2 + 2NaOH _ Na 2 SnO 3 + H 2 O CaO is basic in nature while SiO 2 and CO 2 are acidic in nature.

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