QAIPM-2011-Ch-1784: NEET 2011 Chemistry - Class 12 AIPM-2011-Ch-1784 Solution: Which has the maximum number of molecules among the following?

Step-by-Step Derivation According to Avogadro's hypothesis, the number of molecules is directly proportional to the number of moles of a substance ($\text{Molecules} = \text{Moles} \times N_A$). Therefore, the substance with the highest number of moles will contain the maximum number of molecules. The formula to calculate the number of moles ($n$) is: $n=\frac{\text{Given\ Mass}}{\text{Molar\ Mass}}$ Let's calculate the number of moles for each choice: 1. Option A: 44 g $\mathrm{CO}_{\mathrm{2}}$ � Molar mass of $\mathrm{CO_2} = 12 + (16 \times 2) = 44\text{ g/mol}$ � $\text{Moles} = \frac{44}{44} = 1\text{ mole}$ 2. Option B: 48 g $\mathrm{O}_{\mathrm{3}}$ � Molar mass of $\mathrm{O_3} = 16 \times 3 = 48\text{ g/mol}$ � $\text{Moles} = \frac{48}{48} = 1\text{ mole}$ 3. Option C: 8 g $\mathrm{H}_{\mathrm{2}}$ � Molar mass of $\mathrm{H_2} = 1 \times 2 = 2\text{ g/mol}$ � $\text{Moles} = \frac{8}{2} = 4\text{ moles}$ (Highest value) 4. Option D: 64 g $\mathrm{SO}_{\mathrm{2}}$ � Molar mass of $\mathrm{SO_2} = 32 + (16 \times 2) = 64\text{ g/mol}$ � $\text{Moles} = \frac{64}{64} = 1\text{ mole}$