Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ch-1781: NEET 2011 Chemistry - Class 12 AIPM-2011-Ch-1781 Solution: The half-life of a substance in a certain enzyme-catalysed…

The half-life of a substance in a certain enzyme-catalysed reaction is 138 s. The time required for the concentration of the substance to fall from 1.28 mg L−11.28\ \text{mg L}^{-1} to 0.04 mg L−10.04\ \text{mg L}^{-1} is

Multiple Choice Options

  • A 414 s
  • B 552 s
  • C 690 s
  • D 276 s

Step-by-Step Verified Solution

We know, N = N 0 ( 1 2 ) n Give N 0 (original amount) = 1.28 mg L �1 N (amount of substance left after time T) = 0.04 mg L �1 _ 0.04 1.28 = ( 1 2 ) n _ 1 32 = ( 1 2 ) n _ n = 5 _ Time required = 5 _ t 1/2 = 5 _ 138 = 690 s

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