Verified Solution • 2025–26 Session moderate

QAIPM-2011-Ch-1780: NEET 2011 Chemistry - Class 12 AIPM-2011-Ch-1780 Solution: The rate of the reaction: \(2N_2O_5 4NO_2+O_2\) can be written…

The rate of the reaction: 2N2O5→4NO2+O22N_2O_5\rightarrow 4NO_2+O_2 can be written in three ways. −d[N2O5]dt=k[N2O5]-\frac{d[N_2O_5]}{dt}=k[N_2O_5], d[NO2]dt=k′[N2O5]\frac{d[NO_2]}{dt}=k'[N_2O_5], d[O2]dt=k′′[N2O5]\frac{d[O_2]}{dt}=k''[N_2O_5]. The relationship between k and k' and between k and k'' are

Multiple Choice Options

  • A k′=2k; k′′=kk'=2k;\ k''=k
  • B k′=2k; k′′=k/2k'=2k;\ k''=k/2
  • C k′=2k; k′′=2kk'=2k;\ k''=2k
  • D k′=k; k′′=kk'=k;\ k''=k

Step-by-Step Verified Solution

Rate of disappearance of reactants = Rate of appearance of products _ 1 2 _ d [ N 2 O 5 ] d t = 1 4 d [ N O 2 ] d t = d [ O 2 ] d t _ 1 2 k [ N 2 O 5 ] = 1 4 k _ [ N 2 O 5 ] = k _ [ N 2 O 5 ] _ k 2 = k _ 4 = k _ _ k _ = 2 k ; k _ = k / 2

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