Verified Solution • 2025–26 Session moderate

QAIPMT-2010-Ph-2090: NEET 2010 Physics - Class 12 AIPMT-2010-Ph-2090 Solution: Two positive ions each carrying a charge q are separated by a…

Two positive ions each carrying a charge q are separated by a distance d. If F is the force of repulsion between the ions the number of electrons missing from each ion will be (e being the charge on an electron) 4πϵ0Fd2e2\frac{4\pi\epsilon_0 Fd^2}{e^2} 4πϵ0Fe2d2\sqrt{\frac{4\pi\epsilon_0 Fe^2}{d^2}} 4πϵ0Fd2e2\sqrt{\frac{4\pi\epsilon_0 Fd^2}{e^2}} 4πϵ0Fd2q2\frac{4\pi\epsilon_0 Fd^2}{q^2}

Multiple Choice Options

  • A f f\, f and I4{I \over 4} 4 I _
  • B 3f4{{3f} \over 4} 4 3 f _ and I2{I \over 2} 2 I _
  • C ff f and 3I4{{3I} \over 4} 4 3 I _
  • D f2{f \over 2} 2 f _ and I2{I \over 2} 2 I _

Step-by-Step Verified Solution

By covering aperture, focal length does not change. But intensity is reduced by 1 4 times, as aperture diameter d 2 is covered. _ I' = I - I 4 = 3 I 4 _ New focal length = f and intensity = 3 I 4

Related Learning Resources & Exam Preparation