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QAIPMT-2010-Ph-2085: NEET 2010 Physics - Class 12 AIPMT-2010-Ph-2085 Solution: The potential difference that must be applied to stop the…

The potential difference that must be applied to stop the fastest photoelectrons emitted by a nickel surface having work functions 5.01 eV when ultraviolet light of 200 nm falls on it must be 2.4 V -1.2 V -2.4 V 1.2 V

Multiple Choice Options

  • A 2πμV2\pi \mu V 2 � _ V
  • B πμV\pi \mu V � _ V
  • C π2μV{\pi \over 2}\mu V 2 � _ _ V
  • D 2 μ\mu _ VV V

Step-by-Step Verified Solution

Constant rate at which radius of the loop shrinks d r d t = 1 _ 10 _ 3 m s -1 Magnetic flux linked with the loop is _ = BAcos _ = B( � r 2 )cos0 o = B � r 2 The magnitude of the induced emf is |e| = d _ d t = d d t ( B � r 2 ) = B � 2 r d r d t = 0.025 _ � _ 2 _ 2 _ 10 -2 _ 1 _ 10 -3 = � _ 10 -6 V = � _ V

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