Verified Solution • 2025–26 Session moderate

QAIPMT-2010-Ph-2065: NEET 2010 Physics - Class 12 AIPMT-2010-Ph-2065 Solution: A vibration magnetometer placed in magnetic meridian has a…

A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of 2 sec in earth's horizontal magnetic field of 24 microtesla. When a horizontal field of 18 microtesla is produced opposite to the earth's field by placing a current carrying wire the new time period of magnet will be 1 s 2 s 3 s 4 s

Multiple Choice Options

A A $\to$ _ 1, B $\to$ _ 0, C $\to$ _ 0
B A $\to$ _ 1, B $\to$ _ 0, C $\to$ _ 1
C A $\to$ _ 1, B $\to$ _ 1, C $\to$ _ 0
D A $\to$ _ 0, B $\to$ _ 1, C $\to$ _ 0

Step-by-Step Verified Solution

The Boolen expression for the given combination is output Y = (A + B) � C So it is clear that Y = 1, when A = 1, B = 0 and C = 1

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