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QAIPMT-2010-Ph-2063: NEET 2010 Physics - Class 11 AIPMT-2010-Ph-2063 Solution: A ball is dropped from a high rise platform at t = 0 starting…
A ball is dropped from a high rise platform at t = 0 starting from rest. After 6 seconds another ball is thrown downwards from the same platform with a speed v. The two balls meet at t = 18 s. What is the value of v? (Take g = 10 )
Multiple Choice Options
- A 75 m/s
- B 55 m/s
- C 40 m/s
- D 60 m/s
Step-by-Step Verified Solution
From the question, we can say
distance moved by 1 st ball in 18 s = distance moved by 2 nd ball in 12 s.
So, distance moved by 1 st ball in 18 s
= 1 2 _ 10 _ 18 2 = 1620 m
and distance moved by 2 nd ball in 12 s
= v t + 1 2 g t 2
_ 1620 = v ( 12 ) + 1 2 _ 10 ( 12 ) 2
_ v = 75 m/s