Verified Solution • 2025–26 Session moderate

QAIPMT-2010-Ph-1986: NEET 2010 Physics - Class 12 AIPMT-2010-Ph-1986 Solution: A condenser of capacity C is charged to a potential difference…

A condenser of capacity C is charged to a potential difference of

V_1

. The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser reduces to

V_2

Multiple Choice Options

A $\left(\frac{C(V_1-V_2)^2}{L}\right)^{1/2}$
B $\frac{C(V_1^2-V_2^2)}{L}$
C $\frac{C(V_1^2+V_2^2)}{L}$
D $\left(\frac{C(V_1^2-V_2^2)}{L}\right)^{1/2}$

Step-by-Step Verified Solution

q = q 0 cos _ t _ cos _ t = q q 0 = C V 2 C V 1 = V 2 V 1 Current through the inductor I = d q d t = d d t ( q 0 cos _ _ t ) = - q 0 _ sin _ t _ |I| = C V 1 1 L C [ 1 _ cos 2 _ t ] 1 / 2 = V 1 C L [ 1 _ ( V 2 V 1 ) ] 1 / 2 = ( C ( V 1 2 _ V 2 2 ) L ) 1 2

Related Learning Resources & Exam Preparation

NEET PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring