Verified Solution • 2025–26 Session moderate

QAIPMT-2010-Ph-1984: NEET 2010 Physics - Class 12 AIPMT-2010-Ph-1984 Solution: The electron in the hydrogen atom jumps from excited state (n = …

The electron in the hydrogen atom jumps from excited state (n = 3) to its ground state (n = 1) and the photons thus emitted irradiate a photosensitive material. If the work function of the material is 5.1 eV, the stopping potential is estimated to be (the energy of the electron in nth state En=−13.6n2E_n=-\frac{13.6}{n^2} eV)

Multiple Choice Options

  • A 5.1 V
  • B 12.1 V
  • C 17.2 V
  • D 7 V

Step-by-Step Verified Solution

E = h _ = E 3 - E 1 = _ 13.6 3 2 _ ( _ 13.6 1 2 ) = 12.1 eV Therefore, stopping potential eV 0 = h _ - _ = (12.1 � 5.1) eV V 0 = 7 V

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