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QAIPMT-2010-Ch-2029: NEET 2010 Chemistry - Class 11 AIPMT-2010-Ch-2029 Solution: What is \([H^+]\) in mol/L of a solution that is 0.20 M in…
What is in mol/L of a solution that is 0.20 M in and 0.10 M in ? for
Multiple Choice Options
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Step-by-Step Verified Solution
CH 3 COOH and CH 3 COONa constitute to
form an acidic buffer.
_ pH = pKa + log [ S a l t ] [ A c i d ]
pH = �log(1.8 _ 10 �5 ) + log ( 0.20 ) ( 0.10 )
= 4.74 + log 2
= 4.74 + 0.3010 = 5.041
Now, pH = � log[H + ]
_ 5.041 = � log[H + ]
_ [H + ] = 10 �5.041 = 9.0 _ 10 6
mol L �1