Verified Solution • 2025–26 Session moderate

QAIPMT-2010-Ch-2027: NEET 2010 Chemistry - Class 12 AIPMT-2010-Ch-2027 Solution: During the kinetic study of the reaction, \(2A+B C+D\),…

During the kinetic study of the reaction, 2A+B→C+D2A+B\rightarrow C+D, following results were obtained Run [A]/mol L−1^{-1} [B]/mol L−1^{-1} Initial rate of formation of D/mol L−1^{-1} min−1^{-1} I. 0.1 0.1 6.0×10−36.0\times10^{-3} II. 0.3 0.2 7.2×10−27.2\times10^{-2} III. 0.3 0.4 2.88×10−12.88\times10^{-1} IV. 0.4 0.1 2.40×10−22.40\times10^{-2}. Based on the above data which one of the following is correct?

Multiple Choice Options

  • A Rate = k[A]2[B]k[A]^2[B]
  • B Rate = k[A][B]k[A][B]
  • C Rate = k[A]2[B]2k[A]^2[B]^2
  • D Rate = k[A][B]2k[A][B]^2

Step-by-Step Verified Solution

Rate = k[A] x [B] y For the given situations (I) rate = k(0.1) x (0.1) y = 6.0 _ 10 _ 3 (II) rate = k(0.2) x (0.3) y = 7.2 _ 10 _ 2 (III) rate = k(0.3) x (0.4) y = 2.88 _ 10 _ 1 (IV) rate = k(0.4) x (0.1) y = 2.40 _ 10 _ 2 Dividing eq. (I) by eq. (IV) we get ( 0.1 0.4 ) x ( 0.1 0.1 ) y = 6.0 _ 10 _ 3 2.4 _ 10 _ 2 _ ( 1 4 ) x = ( 1 4 ) 1 _ x = 1 On dividing eq. (II) by eq. (III) we get ( 0.3 0.3 ) x ( 0.2 0.4 ) y = 7.2 _ 10 _ 2 2.88 _ 10 _ 1 _ ( 1 2 ) y = 1 4 _ y = 2 _ Rate = k[A][B] 2

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