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QAIPMT-2010-Ch-2005: NEET 2010 Chemistry - Class 12 AIPMT-2010-Ch-2005 Solution: For the reaction \(N_2O_5(g) 2NO_2(g)+ {1}{2}O_2(g)\) the value …

For the reaction N2O5(g)→2NO2(g)+12O2(g)N_2O_5(g)\rightarrow 2NO_2(g)+\frac{1}{2}O_2(g) the value of rate of disappearance of N2O5N_2O_5 is given as 6.25×10−3 mol L−1 s−16.25\times10^{-3}\ \text{mol L}^{-1}\ \text{s}^{-1}. The rate of formation of NO2NO_2 and O2O_2 is given respectively as

Multiple Choice Options

  • A 6.25×10−3 mol L−1 s−16.25\times10^{-3}\ \text{mol L}^{-1}\ \text{s}^{-1} and 6.25×10−3 mol L−1 s−16.25\times10^{-3}\ \text{mol L}^{-1}\ \text{s}^{-1}
  • B 1.25×10−2 mol L−1 s−11.25\times10^{-2}\ \text{mol L}^{-1}\ \text{s}^{-1} and 3.125×10−3 mol L−1 s−13.125\times10^{-3}\ \text{mol L}^{-1}\ \text{s}^{-1}
  • C 6.25×10−3 mol L−1 s−16.25\times10^{-3}\ \text{mol L}^{-1}\ \text{s}^{-1} and 3.125×10−3 mol L−1 s−13.125\times10^{-3}\ \text{mol L}^{-1}\ \text{s}^{-1}
  • D 1.25×10−2 mol L−1 s−11.25\times10^{-2}\ \text{mol L}^{-1}\ \text{s}^{-1} and 6.25×10−3 mol L−1 s−16.25\times10^{-3}\ \text{mol L}^{-1}\ \text{s}^{-1}

Step-by-Step Verified Solution

N 2 O 5(g) _   2NO 2(g) + 1/2O 2(g) _ d [ N 2 O 5 ] d t = 1 2 d [ N O 2 ] d t = 2 d [ O 2 ] d t _ d [ N O 2 ] d t = _ 2 d [ N 2 O 5 ] d t = 2 _ 6.25 _ 10 mol l -1 sec -1 = 1.25 _ 10 _ 2 mol L _ 1 s _ 1 d [ O 2 ] d t = _ 1 2 d [ N 2 O 5 ] d t = 6.25 _ 10 _ 3 2 = 3.125 _ 10 _ 3 mol L _ 1 s _ 1

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