Verified Solution • 2025–26 Session moderate

QAIPMT-2010-Ch-1996: NEET 2010 Chemistry - Class 11 AIPMT-2010-Ch-1996 Solution: If pH of a saturated solution of \(Ba(OH)_2\) is 12, the value…

If pH of a saturated solution of Ba(OH)2Ba(OH)_2 is 12, the value of its KspK_{sp} is

Multiple Choice Options

  • A 4.00×10−6 M34.00\times10^{-6}\ \text{M}^3
  • B 4.00×10−7 M34.00\times10^{-7}\ \text{M}^3
  • C 5.00×10−6 M35.00\times10^{-6}\ \text{M}^3
  • D 5.00×10−7 M35.00\times10^{-7}\ \text{M}^3

Step-by-Step Verified Solution

Ba(OH) 2 | _ | Ba 2+ | + | 2OH At equilibrium | x | 2x pH = � log[H + ] 12 = � log [H + ] _ [H + ] = 10 �12 As, [H + ][OH � ] = 10 �14 10 �12 [OH � ] = 10 �14 _ [OH � ] = 10 �2 As [OH � ] = 2x = 10 �2 then x = 5.0 _ 10 �3 Now, K sp = [Ba 2+ ][OH � ] 2 K sp = (5 _ 10 �3 ) (10 �2 ) 2 = 5.0 _ 10 �7

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