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QAIPMT-2010-Ch-1949: NEET 2010 Chemistry - Class 12 AIPMT-2010-Ch-1949 Solution: Consider the following relations for emf of an electrochemical…
Consider the following relations for emf of an electrochemical cell: (i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii) EMF of cell = (Reductional potential of anode) + (Reduction potential of cathode) (iv) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode). Which of the above relations are correct?
Multiple Choice Options
- A (iii) and (i)
- B (i) and (ii)
- C (iii) and (iv)
- D (ii) and (iv)
Step-by-Step Verified Solution
EMF of a cell = Reduction potential of cathode
� Reduction potential of anode
= Reduction potential of cathode +
Oxidation potential of anode
= Oxidation potential of anode �
Oxidation potential of cathode.