Verified Solution • 2025–26 Session moderate

QAIPMT-2010-Ch-1942: NEET 2010 Chemistry - Class 11 AIPMT-2010-Ch-1942 Solution: The pressure exerted by 6.0 g of methane gas in a \(0.03\…

The pressure exerted by 6.0 g of methane gas in a

0.03\ \text{m}^3

vessel at

129^\circ C

is (Atomic masses: C = 12.01, H = 1.01 and R = 8.314 J K

^{-1}

mol

^{-1}

)

Step-by-Step Verified Solution

PV = nRT _ P = n R T V = w m R T V = 6 16.05 _ 8.314 _ 402 0.03 = 41648 Pa