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QAIPMT-2009-Ph-2188: NEET 2009 Physics - Class 11 AIPMT-2009-Ph-2188 Solution: The internal energy change in a system that has absorbed 2 kcal …
The internal energy change in a system that has absorbed 2 kcal of heat and done 500 J of work is 6400 J 5400 J 7900 J 8900 J
Multiple Choice Options
- A 3 2 _ M l 2
- B 3 13 _ M l 2
- C 3 1 _ M l 2
- D 3 4 _ M l 2
Step-by-Step Verified Solution
As per theorem of parallel axes :
I = I cm + Ma 2
where I cm = moment of inertia about an axis through centre of mass of rod
I = moment of inertia about parallel axis at distance �a�
Now moment of inertia of thin rod of mass M and
length L about an axis through the midpoint of the
rod and perpendicular to its length is ML 2 /12.
The moment of inertia of a rod about parallel axis at
distance L/2 will be :
ML 2 /12 + M(L/2) 2 = ML 2 /3
As there are 4 rods in square frame, so moment of inertia of entire frame is 4 times the moment of inertia of 1 rod, so it will be (4/3) ML 2