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QAIPMT-2009-Ph-2168: NEET 2009 Physics - Class 12 AIPMT-2009-Ph-2168 Solution: A thin circular ring of mass M and radius R is rotating in a…

A thin circular ring of mass M and radius R is rotating in a horizontal plane about an axis vertical to its plane with a constant angular velocity ω\omega. If two objects each of mass m be attached gently to the opposite ends of a diameter of the ring the ring will then rotate with an angular velocity MωM+2m\frac{M\omega}{M+2m} (M+2m)ωM\frac{(M+2m)\omega}{M} MωM+m\frac{M\omega}{M+m} (M−2m)ωM+2m\frac{(M-2m)\omega}{M+2m}

Multiple Choice Options

  • A 12 J
  • B 6 J
  • C 2 J
  • D 0.6 J

Step-by-Step Verified Solution

Now work done = MB(cos_ 1 � cos_ 2 ) = MB (1 � 1/2) = 2 _ 10 4 _ 6 _ 10 _ 4 2 = 6 J

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