Verified Solution • 2025–26 Session moderate

QAIPMT-2009-Ph-2156: NEET 2009 Physics - Class 12 AIPMT-2009-Ph-2156 Solution: In a Rutherford scattering experiment when a projectile of…

In a Rutherford scattering experiment when a projectile of charge z1z_1 and mass M1M_1 approaches a target nucleus of charge z2z_2 and mass M2M_2 the distance of closest approach is r0r_0. The energy of the projectile is directly proportional to z1z2z_1z_2 inversely proportional to z1z_1 directly proportional to mass M1M_1 directly proportional to M1−M2M_1-M_2

Multiple Choice Options

  • A E→=i^2xy+j^(x2+y2)+k^(3xz−y2)\overrightarrow E = \widehat i2xy + \widehat j\left( {{x^2} + {y^2}} \right) + \widehat k\left( {3xz - {y^2}} \right) E = i 2 x y + j _ ( x 2 + y 2 ) + k ( 3 x z _ y 2 )
  • B E→=i^z3+j^xyz+k^z2\overrightarrow E = \widehat i{z^3} + \widehat jxyz + \widehat k{z^2} E = i z 3 + j _ x yz + k z 2
  • C E→=i^(2xy−z3)+j^xy2+k^3z2x\overrightarrow E = \widehat i\left( {2xy - {z^3}} \right) + \widehat jx{y^2} + \widehat k3{z^2}x E = i ( 2 x y _ z 3 ) + j _ x y 2 + k 3 z 2 x
  • D E→=i^(2xy+z3)+j^x2+k^3xz2\overrightarrow E = \widehat i\left( {2xy + {z^3}} \right) + \widehat j{x^2} + \widehat k3x{z^2} E = i ( 2 x y + z 3 ) + j _ x 2 + k 3 x z 2

Step-by-Step Verified Solution

The electric potential at a point, V = �x 2 y � xz 3 + 4. The field E _ = _ _ _ V = _ ( � V � x i ^ + � V � y j ^ + � V � z k ^ ) _ E _ = i ^ ( 2 x y + z 3 ) + j ^ x 2 + k ^ ( 3 x z 2 )

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