Verified Solution • 2025–26 Session moderate

QAIPMT-2009-Ph-2155: NEET 2009 Physics - Class 11 AIPMT-2009-Ph-2155 Solution: The electric potential at a point (x y z) is given by \(V =…

The electric potential at a point (x y z) is given by

V = -x^2y - xz^3 + 4

The electric field

\vec{E}

at that point is

\vec{E} = \hat{i}2xy + \hat{j}(x^2+y^2) + \hat{k}(3xz-y^2)

\vec{E} = \hat{i}z^3 + \hat{j}xyz + \hat{k}z^2

\vec{E} = \hat{i}(2xy-z^3) + \hat{j}xy^2 + \hat{k}3z^2x

\vec{E} = \hat{i}(2xy+z^3) + \hat{j}x^2 + \hat{k}3xz^2

Step-by-Step Verified Solution

F _ = 6 i ^ _ 8 j ^ + 10 k ^ | F _ | = 36 + 64 + 100 = 200 N = 10 2 N Acceleration, a = 1 m s �2 _ M a s s , M = 10 2 1 = 10 2 k g