Verified Solution • 2025–26 Session moderate

QAIPMT-2009-Ph-2154: NEET 2009 Physics - Class 11 AIPMT-2009-Ph-2154 Solution: A body under the action of a force \( {F} = 6 {i} - 8 {j} + 10…

A body under the action of a force

\vec{F} = 6\hat{i} - 8\hat{j} + 10\hat{k}

acquires an acceleration of

1\ \text{m/s}^2

. The mass of this body must be 10 kg 20 kg

10\sqrt{2}\ \text{kg}

2\sqrt{10}\ \text{kg}

Multiple Choice Options

A y = (0.02) m sin (15.7 x $-$ _ 2010t)
B y = (0.02) m sin (15.7 x + 2010t)
C y = (0.02) m sin (7.85 x $-$ _ 1005t)
D y = (0.02) m sin (7.85 x + 1005t)

Step-by-Step Verified Solution

As A = 2 c m , _ k = 128 m s _ 1 , 5 _ = 4 , _ = 4 5 m y = A sin (kx � _ t) k = 2 � _ = 2 � _ 5 4 = 31.4 4 = 7.85 _ _ = 128 _ 7.85 = 1005 so y = 0.02 m sin (7.85x � 1005 t)

Related Learning Resources & Exam Preparation

NEET PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring