Verified Solution • 2025–26 Session moderate

QAIPMT-2009-Ph-2153: NEET 2009 Physics - Class 12 AIPMT-2009-Ph-2153 Solution: A wave in a string has an amplitude of 2 cm. The wave travels…

A wave in a string has an amplitude of 2 cm. The wave travels in the +ve direction of x axis with a speed of 128 m/s and it is noted that 5 complete waves fit in 4 m length of the string. The equation describing the wave is y=(0.02)msin⁡(15.7x−2010t)y = (0.02)\text{m} \sin(15.7x - 2010t) y=(0.02)msin⁡(15.7x+2010t)y = (0.02)\text{m} \sin(15.7x + 2010t) y=(0.02)msin⁡(7.85x−1005t)y = (0.02)\text{m} \sin(7.85x - 1005t) y=(0.02)msin⁡(7.85x+1005t)y = (0.02)\text{m} \sin(7.85x + 1005t)

Multiple Choice Options

  • A 4.8 π\pi � μ\mu _ V
  • B 0.8 π\pi � μ\mu _ V
  • C 1.6 π\pi � μ\mu _ V
  • D 3.2 π\pi � μ\mu _ V

Step-by-Step Verified Solution

Constant rate at which radius of the loop shrinks d r d t = 2 _ 10 _ 3 m s -1 Magnetic flux linked with the loop is _ = BAcos _ = B( � r 2 )cos0 o = B � r 2 The magnitude of the induced emf is |e| = d _ d t = d d t ( B � r 2 ) = B � 2 r d r d t = 0.04 _ � _ 2 _ 2 _ 10 -2 _ 2 _ 10 -3 = 3.2 � _ 10 -6 V = 3.2 � _ V

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