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QAIPMT-2009-Ch-2136: NEET 2009 Chemistry - Class 11 AIPMT-2009-Ch-2136 Solution: What is the \([OH^-]\) in the final solution prepared by mixing …

What is the [OH−][OH^-] in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M Ba(OH)2Ba(OH)_2?

Multiple Choice Options

  • A 0.40 M
  • B 0.0050 M
  • C 0.12 M
  • D 0.10 M

Step-by-Step Verified Solution

Number of equivalents of H + = 20.0 _ 0.050 milliequivalents = 1.0 milliequivalents Number of equivalents of OH � = 2 _ 30.0 _ 0.10 = 6.0 milliequivalents _ Equivalents of OH - left after neutralization = 6 � 1 = 5 milliequivalents Total volume after neutralization = 20.0 + 30.0 mL = 50 mL [OH - ] = 5 50 = 0.1 M

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