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QAIPMT-2009-Ch-2133: NEET 2009 Chemistry - Class 12 AIPMT-2009-Ch-2133 Solution: The equivalent conductance of M/32 solution of a weak monobasic …

The equivalent conductance of M/32 solution of a weak monobasic acid is 8.0 mho cm28.0\ \text{mho cm}^2 and at infinite dilution is 400 mho cm2400\ \text{mho cm}^2. The dissociation constant of this acid is

Multiple Choice Options

  • A 1.25×10−61.25\times10^{-6}
  • B 6.25×10−46.25\times10^{-4}
  • C 1.25×10−41.25\times10^{-4}
  • D 1.25×10−51.25\times10^{-5}

Step-by-Step Verified Solution

The degree of dissociation ( _ ) _ = 8 400 = 2 _ 10 -2 From Ostwald�s dilution law for weak monobasic acid, we have k c = C _ 2 = 1 32 _ ( 2 _ 10 _ 2 ) 2 = 1.25 _ 10 -5

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