Verified Solution • 2025–26 Session moderate

QAIPMT-2009-Ch-2092: NEET 2009 Chemistry - Class 11 AIPMT-2009-Ch-2092 Solution: From the following bond energies: H-H bond energy: \(431.37\…

From the following bond energies: H-H bond energy: 431.37 kJ mol−1431.37\ \text{kJ mol}^{-1}; C=C bond energy: 606.10 kJ mol−1606.10\ \text{kJ mol}^{-1}; C-C bond energy: 336.49 kJ mol−1336.49\ \text{kJ mol}^{-1}; C-H bond energy: 410.50 kJ mol−1410.50\ \text{kJ mol}^{-1}. Enthalpy for the reaction will be

Multiple Choice Options

  • A −243.6 kJ mol−1-243.6\ \text{kJ mol}^{-1}
  • B −120.0 kJ mol−1-120.0\ \text{kJ mol}^{-1}
  • C 553.0 kJ mol−1553.0\ \text{kJ mol}^{-1}
  • D 1523.6 kJ mol−11523.6\ \text{kJ mol}^{-1}

Step-by-Step Verified Solution

_ H reaction = _(Bond enthalpy) reactants � _(Bond enthalpy) products = [B.E (C-C) + B.E (H-H) + 4 _ B.E (C-H) ] - [B.E (C-C) + 6 _ B.E (C-H) ] = [606.10 + 4(410.50) + 431.37] � [336.49 + 6(410.50)] = 2679.47 � 2799.49 = � 120.02 kJ mol �1

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