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QAIPMT-2008-Ch-2189: NEET 2009 Physics - Class 11 AIPMT-2008-Ch-2189 Solution: The internal energy change in a system that has absorbed 2 kcal …
The internal energy change in a system that has absorbed 2 kcal of heat and done 500 J of work is
Multiple Choice Options
- A 6400 J
- B 5400 J
- C 7900 J
- D 8900 J
Step-by-Step Verified Solution
When a quantity Q of heat is supplied to a system it is used to do an amount of work W by the system and to increase the internal energy of the system by �U :
Q = �U + W
Here, Q given in kilo calories is converted into joule.
Therefore Q = 2_1000_4.2 J = 8400 J
The increase the internal energy
�U = Q � W = 8400 � 500 = 7900 J