Verified Solution • 2025–26 Session moderate

QAIPMT-2008-Ph-2284: NEET 2008 Physics - Class 11 AIPMT-2008-Ph-2284 Solution: A closed loop PQRS carrying a current is placed in a uniform…

A closed loop PQRS carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments PS SR and RQ are F1F2F_1 F_2 and F3F_3 respectively and are in the plane of the paper and along the directions shown the force on the segment QP is (F3−F1)2−F22(F_3-F_1)^2-F_2^2 F3−F1+F2F_3-F_1+F_2 F3−F1−F2F_3-F_1-F_2 (F3−F1)2+F22\sqrt{(F_3-F_1)^2+F_2^2}

Multiple Choice Options

  • A 12.3 kW
  • B 7.0 kW
  • C 8.1 kW
  • D 10.2 kW

Step-by-Step Verified Solution

It is seen that input power to turbine will be the potential energy due to water falling in a second which is equal to mgh = 15_10_60 = 9000 watt Now power generated by turbine is 10% less than above value equal to (9000 � 900) watt = 8100 watt = 8.1 kW

Related Learning Resources & Exam Preparation

NEET PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring