Verified Solution • 2025–26 Session moderate

QAIPMT-2008-Ph-2279: NEET 2008 Physics - Class 12 AIPMT-2008-Ph-2279 Solution: The electric potential at a point in free space due to charge Q …

The electric potential at a point in free space due to charge Q coulomb is

Q \times 10^{11}

volts. The electric field at that point is

4\pi\epsilon_0 Q \times 10^{20}\ \text{volt/m}

12\pi\epsilon_0 Q \times 10^{22}\ \text{volt/m}

4\pi\epsilon_0 Q \times 10^{22}\ \text{volt/m}

12\pi\epsilon_0 Q \times 10^{20}\ \text{volt/m}

Multiple Choice Options

A E along KO
B 3E along OK
C 3E along KO
D E along OK

Step-by-Step Verified Solution

By the symmetry of the figure, the electric fields at O due to the portions AC and BD are equal in magnitude and opposite in direction. So, they cancel each other. Similarly, the field at O due to CD and AKB are equal in magnitude but opposite in direction. Therefore, the electric field at the centre due to the charge on the part ACDB is E along OK.

Related Learning Resources & Exam Preparation

NEET PYQ Question Bank

Browse year-wise authentic previous years' questions with solutions

Authentic CBT Mock Tests

Simulate official exam environment with live timer and percentile scoring