Verified Solution • 2025–26 Session moderate

QAIPMT-2008-Ph-2263: NEET 2008 Physics - Class 12 AIPMT-2008-Ph-2263 Solution: A long solenoid has 500 turns. When a current of 2 ampere is…

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10−34\times10^{-3} Wb. The self-inductance of the solenoid is

Multiple Choice Options

  • A 1.0 henry
  • B 4.0 henry
  • C 2.5 henry
  • D 2.0 henry

Step-by-Step Verified Solution

Total number of turns in the solenoid, N = 500 Current, I = 2A. Magnetic flux linked with each turn = 4 _ 10 �3 Wb Self inductance of coil : L = N _ I = 500 _ 4 _ 10 3 2 = 1 H

Related Learning Resources & Exam Preparation