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QAIPMT-2008-Ph-2262: NEET 2008 Physics - Class 12 AIPMT-2008-Ph-2262 Solution: A long solenoid has 500 turns. When a current of 2 ampere is…
A long solenoid has 500 turns. When a current of 2 ampere is passed through it the resulting magnetic flux linked with each turn of the solenoid is . The self-inductance of the solenoid is 1.0 henry 4.0 henry 2.5 henry 2.0 henry
Multiple Choice Options
- A 2.0 ohm
- B zero
- C 1.0 ohm
- D 0.5 ohm
Step-by-Step Verified Solution
Here E > E R R + r , hence the lengths 110 cm and 100 cm are interchanged.
Without being short-circuited through R, only the battery E is balanced.
E = V L _ l 1 = V L _ 110 ...(i)
When R is connected across E, R i = V L _ l 2
_ R ( E R + r ) = V L _ 100 ...(ii)
Dividing (i) by (ii), we get
R + r R = 110 100
_ 100 R + 100 r = 110 R
_ 10 R = 100 r
_ r = 10 R 100 = 10 _ 10 100 ( _ R = 10 � )
_ r = 1 � .