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QAIPMT-2008-Ph-2256: NEET 2008 Physics - Class 11 AIPMT-2008-Ph-2256 Solution: Two simple harmonic motions of angular frequency 100 and…

Two simple harmonic motions of angular frequency 100 and

1000\ \text{rad s}^{-1}

have the same displacement amplitude. The ratio of their maximum acceleration is

Multiple Choice Options

A $1:10^3$
B $1:10^4$
C $1:10$
D $1:10^2$

Step-by-Step Verified Solution

Maximum acceleration of a particle in the simple harmonic motion is directly proportional to the square of angular frequency i.e. a _ _ 2 _ a 1 a 2 = _ 1 2 _ 2 2 = ( 100 ) 2 ( 1000 ) 2 = 1 100 _ a 1 : a 2 = 1 : 10 2 .

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